How does my book go from this step to the next (trig)

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SUMMARY

The discussion focuses on the simplification of the trigonometric expression T(θ) = 2 cos²(θ) + sin²(θ) - sin(θ) + 3 to T'(θ) = -2 cos(θ) sin(θ) - cos(θ). The key transformation involves using the Pythagorean identity sin²(θ) + cos²(θ) = 1 to substitute sin²(θ) with 1 - cos²(θ). This substitution simplifies the expression significantly, leading to the final derivative form. Participants emphasize the importance of recognizing trigonometric identities for effective simplification.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sin²(θ) + cos²(θ) = 1
  • Familiarity with differentiation of trigonometric functions
  • Basic algebraic manipulation skills
  • Knowledge of function notation and derivatives
NEXT STEPS
  • Study the application of the Pythagorean identity in trigonometric simplifications
  • Learn about differentiation techniques for trigonometric functions
  • Explore advanced trigonometric identities and their proofs
  • Practice problems involving the simplification of trigonometric expressions
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to improve their understanding of trigonometric functions and their derivatives.

frasifrasi
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OK, in an example, we are given:

"T(θ)= 2 cos^2 (θ) +sin^2 (θ) − sin (θ) + 3
=cos^2 (θ) − sin θ + 4.
Then Tθ(θ)= −2 cos θ sin θ − cos θ =
−cos θ(2 sinθ + 1)"

can anyone explain what happened from step 1 to 2--i am completely lost?

Thanks.
 
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frasifrasi said:
OK, in an example, we are given:

"T(θ)= 2 cos^2 (θ) +sin^2 (θ) − sin (θ) + 3
=cos^2 (θ) − sin θ + 4.
Then Tθ(θ)= −2 cos θ sin θ − cos θ =
−cos θ(2 sinθ + 1)"

can anyone explain what happened from step 1 to 2--i am completely lost?

[tex]\sin^2 \theta + \cos^2 \theta = 1[/tex]
so
[tex]\sin^2 \theta = 1 - \cos^2 \theta[/tex]
Now, substitute in for step 1 and simplify.
 
Geez, I am embarassed.
 

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