How Does Pascal's Principle Apply to Hydraulic Systems?

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SUMMARY

This discussion focuses on applying Pascal's Principle to hydraulic systems, specifically in the context of a dentist's chair and a hydraulic lift. The calculations reveal that the pressure in the fluid when the dentist operates the chair is 1.27 x 10^6 Pa, requiring a force of 100 N on the small piston. For the hydraulic lift, a force of 177 N is needed to raise a 900 kg car, with the input piston needing to be depressed 100 m to lift the vehicle 2 m. The equations utilized include F=mg, F/F2 = A/A2, and PA= F.

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  • Understanding of Pascal's Principle in fluid mechanics
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  • Familiarity with the concept of hydraulic systems and their components
  • Ability to perform unit conversions and area calculations
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Homework Statement


Imagine a hydraulically operated dentist's chair having a mass of 200kg, and in it is stiing a 54.8kg patient. The large piston below the chair has 5cm(diameter), while the small piston, moved by a pedal on which the dentist steps, has 1cm(diameter). What's the pressure in the interconnecting fluid when the dentist operates the chair? How much force must he exert on the small piston?

2. A hydraulic lift consists of two interconnected pistons filed with a common working liquid. If the areas of the piston faces are 64cm^2 and 3200cm^2 and if 900kg car rests on the latter, how much force must be exerted to raise the vehicle very slowly?
If the car is to be raised 2m, how far must the input piston be depressed?

Homework Equations


F=mg
F/F2 =A/A2
PA= F

The Attempt at a Solution


The answers for 1 are 1.27 x10^6 Pa and 100N...
Answers for 2 are 177N and 100m.

Please help.:(! I have no idea how to get these answers :((
 
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P= F/A
Find the total weight on the larger piston. Then find the pressure using the relevant equation.
 

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