stateofdogma
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no nevermind, i think it works if you consider the dot product a distribution over a negative differential.
This discussion focuses on deriving the work and kinetic energy for a pendulum using the integral of force over displacement, specifically ∫force⋅ds. The participants clarify that the correct expression for work done by gravity is W = mgR(cos(θ) - cos(θ₀)), where θ₀ is the initial angle. The confusion arises when interpreting the signs of the kinetic energy change, Δk, particularly when the direction of force and displacement are aligned or opposed. Ultimately, the discussion emphasizes the importance of correctly applying the work-kinetic energy theorem and understanding the relationship between potential and kinetic energy in pendulum motion.
PREREQUISITESStudents of physics, educators teaching mechanics, and anyone interested in understanding the dynamics of pendulum motion and energy transformations.
Not sure what you mean by that, but to be clear, no, ds does not mean abs(ds). If the range "a to b" is such that the variable of integration, x say, decreases from 'lower' bound a to 'upper' bound b then dx is negative. E.g. ##\int_a^b f.dx = -\int_b^a f.dx##.stateofdogma said:no nevermind, i think it works if you consider the dot product a distribution over a negative differential.