How Does Ramp Angle Affect the Maximum Height Reached by a Block?

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SUMMARY

The discussion centers on the physics problem of determining the maximum height reached by a block shot up a frictionless slope at different angles, specifically 40 degrees and 20 degrees. The key takeaway is the application of the conservation of energy principle, where kinetic energy (KE) and potential energy (PE) are considered constant. The initial speed, denoted as v, is not required for calculating the height at which the block comes to a stop, as the energy conservation equation suffices to solve the problem.

PREREQUISITES
  • Understanding of kinetic energy (KE) and potential energy (PE) concepts.
  • Familiarity with the conservation of energy principle in physics.
  • Basic knowledge of trigonometric functions related to angles.
  • Ability to apply equations of motion in a frictionless environment.
NEXT STEPS
  • Study the conservation of energy in mechanical systems.
  • Learn how to apply trigonometric functions to resolve forces on inclined planes.
  • Explore the derivation of maximum height equations in projectile motion.
  • Investigate the effects of different angles on the trajectory of projectiles.
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of energy principles in action.

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Homework Statement


A block is shot up a frictionless 40degree slope with intial speed v. It reaches height h before sliding back down. The same block is shot with the same speed up a frictionless 20 degree slope. On this new slope, the block reaches height?


Homework Equations



1/2 mv^2 I'm not sure how to transfer this equation for speed and height when dealing with angles



The Attempt at a Solution

 
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girlsnguitars said:
A block is shot up a frictionless 40degree slope with intial speed v. It reaches height h before sliding back down. The same block is shot with the same speed up a frictionless 20 degree slope. On this new slope, the block reaches height?

1/2 mv^2 I'm not sure how to transfer this equation for speed and height when dealing with angles

Hi girlsnguitars! :smile:

You don't need speed (except that you want the height at which the speed is zero :wink:).

Just use KE + PE = constant. :smile:
 
@girlsnguitars
Hi,
would you mind posting your answer when, or if, you get it? Thanks
 

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