How Does Reduced Gravity on the Moon Affect a Ballistic Pendulum Experiment?

Click For Summary
SUMMARY

The discussion centers on the effects of reduced gravity on the Moon on a ballistic pendulum experiment. Participants concluded that while the gravitational force is lower on the Moon (4.905 m/s² compared to Earth's 9.81 m/s²), the pendulum's height would increase, resulting in the same initial velocity (Vi) of 1.27 m/s when calculated. The key equations used include Vi = √(2gh), where 'g' represents gravitational acceleration and 'h' is the height. Thus, the experiment's outcomes remain consistent despite the differences in gravitational force.

PREREQUISITES
  • Understanding of kinetic energy and initial velocity calculations
  • Familiarity with the principles of inelastic collisions
  • Knowledge of gravitational acceleration values on Earth and the Moon
  • Basic proficiency in using physics equations related to motion
NEXT STEPS
  • Study the principles of ballistic pendulum experiments
  • Explore the effects of gravity on motion in different celestial environments
  • Learn about inelastic collisions and their implications in physics
  • Investigate the calculations for gravitational acceleration on other celestial bodies
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in the effects of gravity on motion in different environments.

Jac8897
Messages
25
Reaction score
0

Homework Statement


How would doing this experiment in the moom effect the experiment ?

"the experiment in lunching a ball against a pendulum and making an inelastic collision find the kenitic engergy and the inital velocity"

Homework Equations


I found all the answers and I assume the experiment in the moon would yield the same kenitic energy " I know the gravity is less but I also assuming the height of the combination would rise higher than the Earth therefore balancing the equation"

earth
"Vi= ((2*9.81*.0821)square-root )
Vi=1.27m/s

moon " assuming the gravity is half the Earth (4.905m/s^2) and therefore assuming the pendullum is will go twice as height (.1642m)

Vi=((2*4.905*.1642)square-root)
Vi=1.27m/s

"I said the experiment being done in the moom with the same materials use in the Earth would give the same Vi because less gravity would balance with higher "H" height.

that's my answer make sense

thank you! very much


The Attempt at a Solution

 
Physics news on Phys.org
Your intuition is correct. The actual collision is exactly the same. The difference would be in the height to witch the pendulum would swing.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
6K
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
9K
Replies
1
Views
2K
Replies
33
Views
21K
  • · Replies 3 ·
Replies
3
Views
16K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
5K