A certain pendulum clock that works perfectly on Earth is taken to the moon, where g = 1.62 m/s^2. Acceleration of gravity is 9.81 m/s^2 on Earth. THe clock is started at 12:00:00 AM and runs for 22 h.(adsbygoogle = window.adsbygoogle || []).push({});

What will be the reading for the hours on the moon? answer in h

T = 1 second

g = 9.81

T = 2pi * square root of length/g or rearrange into g (T/2pi)^2 = l

l = 0.248

g = 1.63

T = 2pi * square root of l/1.63

T = 2.453

22h * 3600s = 79200 sec

79200/2.453 = 32286.99552

32286.99552/3600 = 8.9686 hours

i also tried

22*3600 = 79200s

79200 = 2pi * square root of l/9.81

l = 1557100708

T = 2pi *square root of 1557100708/1.63

T = 194197.8499s

194197.8499s / 3600 = 53.9438472 hr

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# Homework Help: Reading of a pendulum clock from the earth to the moon

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