How Does Reducing Excitation Affect a Synchronous Induction Motor's Performance?

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SUMMARY

The discussion focuses on the performance impact of reducing excitation in a synchronous motor, specifically a star-connected, three-phase synchronous induction motor. Initially, the motor operates at a generated electromotive force (emf) of 245V with a load angle of 11.6 degrees. Upon reducing excitation by 10%, the new emf is calculated to be 220.5V. The discussion highlights that while the load torque remains constant, the power factor becomes leading, and the load angle increases, indicating a change in the active power drawn by the motor.

PREREQUISITES
  • Understanding of synchronous motor operation and characteristics
  • Knowledge of phasor diagrams in electrical engineering
  • Familiarity with the concepts of electromotive force (emf) and load angle
  • Basic principles of power factor and its implications in motor performance
NEXT STEPS
  • Study the effects of excitation on synchronous motor performance
  • Learn about phasor diagram construction for synchronous motors
  • Research the relationship between load angle and power factor in synchronous motors
  • Explore the differences between synchronous motors and induction motors
USEFUL FOR

Electrical engineers, students studying motor control, and professionals involved in motor performance optimization will benefit from this discussion.

Laa
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Homework Statement


(i) A star-connected, three-phase synchronous induction motor takes a current of 10 amps from a 415 volt supply at unity power factor when supplying a steady load. If the synchronous reactance is 5 ohms/phase and the resistance is negligible, draw the phasor diagram and calculate the value of the generated emf and the load angle.

(ii) If the excitation is reduced by 10% and, as a consequence the generated e.m.f. is reduced by 10%, calculate the new value of the generated e.m.f E, the stator current, the power factor and the load angle, assuming that the load does not change[/B]

Homework Equations

The Attempt at a Solution


For part (i) I have the emf calculated as 245V and the load angle as 11.6 degrees

I am struggling with part (i). I have the new emf at 220.5V but don't know where to go from there.

If I do the same equation for load angle as in part one it doesn't work.

Any help appreciated.
 
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Hi Laa, welcome to PF!

Laa said:
I am struggling with part (i). I have the new emf at 220.5V but don't know where to go from there.
Since the load torque doesn't change and it's a 'synchronous' motor, what does that tell you about the active power drawn by the motor?
 
cnh1995 said:
Hi Laa, welcome to PF!Since the load torque doesn't change and it's a 'synchronous' motor, what does that tell you about the active power drawn by the motor?

Hi, thanks for the quick reply.

Not quite sure what you are getting at there but as the excitation has been reduced, power factor will be leading and the load angle will increase. The value of the stator current should remain the same
 
Laa said:
synchronous induction motor

By the way, that is wrong. Synchronous motors and induction motors are two kinds of motors. There is no such thing as synchronous induction motor. The problem is for a synchronous motor.
cnh1995 said:
Since the load torque doesn't change and it's a 'synchronous' motor, what does that tell you about the active power drawn by the motor?

Following up on that clue. How does the speed of a synchronous motor change with excitation change?
 
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Laa said:
The value of the stator current should remain the same
Why?
 

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