How Does Resistivity Affect Current Flow in Unconventional Conductors?

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SUMMARY

This discussion focuses on calculating the resistance and expected current flow in unconventional conductors, specifically a rubber band and a penny. The resistance formula used is R = ρL/A, where ρ is the resistivity (1E13 Ω·m for the rubber band), L is the length, and A is the cross-sectional area. The penny's resistivity must be sourced from copper values. The calculations involve a 19 cm long rubber band with a 2.2 mm diameter and a penny that is 1 mm thick and 2 cm in diameter, connected to a 108-V power supply.

PREREQUISITES
  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with resistivity concepts and units
  • Ability to calculate cross-sectional area of cylindrical objects
  • Knowledge of unit conversions (e.g., mm to meters)
NEXT STEPS
  • Research the resistivity of copper for accurate calculations
  • Learn how to calculate the cross-sectional area of different shapes
  • Explore the effects of varying resistivity on current flow
  • Study practical applications of unconventional conductors in electronics
USEFUL FOR

Students in physics or electrical engineering, educators teaching resistance concepts, and hobbyists experimenting with unconventional materials in electrical circuits.

jen0519
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Homework Statement


(a) Assuming a resistivity of 1E13 (horseshoe thing)m, calculate the resistance between the ends of a rubber band that is 19 cm long and 2.2 mm in diameter.


(b) Calculate the resistance between the 'heads' and 'tails' sides of a penny that is 1 mm thick and 2 cm in diameter.


(c) WARNING! Do not try this at home! What is the expected current that each would carry if it were connected across a 108-V power supply?
rubber band (A)
penny (A)

Homework Equations



R=pL/a

The Attempt at a Solution



So I thought for the first one that I would use R =pL/A but I think you have to change some of the numbers and I'm not sure how.
 
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jen0519 said:

Homework Statement


(a) Assuming a resistivity of 1E13 (horseshoe thing)m, calculate the resistance between the ends of a rubber band that is 19 cm long and 2.2 mm in diameter.


(b) Calculate the resistance between the 'heads' and 'tails' sides of a penny that is 1 mm thick and 2 cm in diameter.


(c) WARNING! Do not try this at home! What is the expected current that each would carry if it were connected across a 108-V power supply?
rubber band (A)
penny (A)


Homework Equations



R=pL/a


The Attempt at a Solution



So I thought for the first one that I would use R =pL/A but I think you have to change some of the numbers and I'm not sure how.

Welcome to the PF. Yes, that is the correct equation to use. You are given the resistivity rho, and just need to use the dimensions you are given to get the length L and the cross-sectional area A. Be careful with your units...

And for the penny, you will need to look up the resistivity rho number of copper.
 

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