How Does Reversing Current Direction Affect Magnet Position in a Coil?

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SUMMARY

The discussion centers on the behavior of a cylindrical permanent magnet within a cylindrical coil when the direction of current is reversed. Initially, with current flowing such that side A of the coil is the south pole and side B is the north pole, the magnet moves towards side A and settles at the center. When the current direction is reversed, making side A the north pole and side B the south pole, the north end of the magnet aligns with the outside surface of side B, similar to the interaction between two permanent magnets.

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carpekd
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Hello all,

In the sketch attached below, I have a cylindrical coil with a cylindrical permanent magnet located in the center (assume the magnet can only move in the axial A-B direction). It is my understanding that if the coil had current flowing through it so that side A was the south pole and side B was the north, and the permanent magnet started in the position shown, the permanent magnet would move towards A and settle in the center of the coil (please correct me if that is inaccurate). What I can't visualize is where the permanent magnet would settle (again starting from the position shown) if the current was reversed and the A side was the North pole and the B side was the south pole... Would the north end of the magnet (the outside surface) line up with the outside surface of the B side on the coil?

Thanks for your help

- confused mech engineer
 

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carpekd said:
Hello all,

Would the north end of the magnet (the outside surface) line up with the outside surface of the B side on the coil?

Yes. It would be just like two permanent magnets stuck together at a single N-S edge.
 
Thanks for clearing that up!
 

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