How Does Superposition Principle Apply to Forces in a Three-Charge System?

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SUMMARY

The discussion focuses on calculating the net force acting on a 2uC point charge located at 40cm on the +x-axis due to two identical point charges (Q=3uC) positioned 60cm apart on the y-axis. The force between the two charges is calculated to be 0.225N using the formula F = kq(1)q(2)/r^2. The principle of superposition is applied to determine the net force on the 2uC charge, requiring the use of the diagonal length in a right triangle formed by the charges to accurately compute the resultant force.

PREREQUISITES
  • Understanding of Coulomb's Law (F = kq(1)q(2)/r^2)
  • Knowledge of the principle of superposition in physics
  • Ability to analyze forces in a two-dimensional coordinate system
  • Familiarity with basic trigonometry for calculating diagonal lengths
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  • Study the application of the superposition principle in electrostatics
  • Learn how to calculate forces in three-dimensional charge systems
  • Explore vector addition of forces in physics
  • Investigate the effects of varying charge magnitudes and distances on net force
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Physics students, educators, and anyone interested in understanding electrostatic forces and the application of the superposition principle in multi-charge systems.

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Homework Statement


Two identical point charges (Q=3uC) are situated 60cm apart on the y-axis equidistant from the origin. A 2uC point charge lies at 40cm on the + x-axis. What is the magnitude and direction of the net force on the 2uC charge.



Homework Equations


F= kq(1)q(2)/r^2


The Attempt at a Solution


i figured the force between the two charges on the y-axis to be .225N using the above equation, but i do not see how that value is going to have any affect on the 2uC charge.
 
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use superposition

if you draw lines from each Q to the 2uC you will see you have a triangle in order to find the force effecting 2 you need to use that diagonal length as R for F=KQQ/R^2 you will be able to find this pretty easily because you'll see the right triangle forming at the origin.

The value from each will be the same because the distance is the same, so you should find that its just twice as large as one side.
 
HINT: What does the principle of superposition say?

Edit: Beaten to it ...
 

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