How Does Temperature Affect Pressure in a Gas Reaction?

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SUMMARY

The discussion focuses on calculating the pressure in a 20-liter stainless steel container after a reaction between hydrogen and oxygen gases at two different temperatures: 25 degrees Celsius and 125 degrees Celsius. Utilizing Dalton's Law of Partial Pressures, the initial pressures of hydrogen (2 atm) and oxygen (3 atm) are considered, along with the vapor pressure of water produced during the reaction. At 25 degrees Celsius, the total pressure is calculated to be approximately 2.03 atm, while at 125 degrees Celsius, the total pressure exceeds 2 atm due to the complete evaporation of water vapor.

PREREQUISITES
  • Understanding of Dalton's Law of Partial Pressures
  • Knowledge of gas laws and behavior at varying temperatures
  • Familiarity with the ideal gas equation
  • Basic chemistry concepts, including balanced chemical equations
NEXT STEPS
  • Study the ideal gas law and its applications in real-world scenarios
  • Learn about the calculation of vapor pressures, specifically for water at different temperatures
  • Explore the implications of superheated gases in chemical reactions
  • Investigate the stoichiometry of gas reactions and their impact on pressure changes
USEFUL FOR

Chemistry students, chemical engineers, and professionals involved in gas reaction processes will benefit from this discussion, particularly those focusing on thermodynamics and reaction kinetics.

Vigo
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A 20 liter stainless steel container was charged with 2 atm of hydrogen gas and 3 atm of oxygen gas. A spark ignited the mixture, producing water. What is the pressere in the tank at 25 degrees C?

If the reaction in the above problem occurred at 125 degrees C, what would the pressure in the tank be? I know that this problem has to do with Dalton's Law of Partial Pressures and since water is involved, the pressure of water vapor will have to be factored in. But other than that, this problem is much more complex than what we have been doing and I would appreciate some help with it. Thanks.
 
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  1. xs O2 pressure is 2 atm, assuming absolute pressure and 25 C.
  2. ~ 2 mol H2O formed at 25 C in 20 liters,
  3. is 2.03 atm. (2.00 + 25/760, strictly + Poynting correction to water vapor pressure, negligible under xs O2 pressure).
  4. At 125 C, PH2O > 2 atm, totally evaporated, and PTotal = PO2(125 C) + PDry/Superheated.
 
Vigo said:
A 20 liter stainless steel container was charged with 2 atm of hydrogen gas and 3 atm of oxygen gas. A spark ignited the mixture, producing water. What is the pressere in the tank at 25 degrees C?

If the reaction in the above problem occurred at 125 degrees C, what would the pressure in the tank be?I know that this problem has to do with Dalton's Law of Partial Pressures and since water is involved, the pressure of water vapor will have to be factored in. But other than that, this problem is much more complex than what we have been doing and I would appreciate some help with it. Thanks.
In the initial state, if you have 20 liters of gas at 5 atm and 25 C, what is the total number of moles of gas that you have? From this, how many moles of oxygen do you have and how many moles of hydrogen do you have? What is the balanced chemical equation for the reaction of oxygen and hydrogen?
 

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