How does the change in diameter relate to the change in length?

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SUMMARY

The discussion focuses on calculating the change in diameter of a copper rod subjected to thermal expansion. The linear coefficient of thermal expansion (LCTE) for copper is established at 17 x 10^-6 / °C, with a calculated coefficient of 16.75 x 10^-6 / °C based on experimental data. The change in length of the rod is determined to be 0.773 mm, and the relationship between diameter and length is clarified, indicating that the same thermal expansion formula applies. The discussion emphasizes the need for initial measurements of diameter or volume to accurately determine changes in diameter.

PREREQUISITES
  • Understanding of linear thermal expansion and the linear coefficient of thermal expansion (LCTE).
  • Familiarity with basic physics concepts related to temperature change and material properties.
  • Knowledge of copper's thermal expansion characteristics.
  • Ability to perform calculations involving linear dimensions and thermal expansion formulas.
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  • Learn how to derive diameter from volume and mass using density calculations.
  • Explore the concept of isotropy and anisotropy in materials science.
  • Study practical applications of thermal expansion in engineering and manufacturing processes.
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demonslayer42
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Homework Statement



Find the change in diameter of the metal rod.

So I did a lab in class. We heated up a metal rod by putting it in a "jacket" and heating it with steam and it expanded. We were asked to calculate the liner coefficient. Well I did that just fine. I determine that the rod was copper. But how do I fined the change in diameter?

Length of Rod: 600mm

Temperature initial : 22.5 C
Temperature Final : 99.4 C
Change in Temperature :76.9 C

X initial: 5.849mm
X final 6.622mm
Change in length = .773mm

Change in Length = coefficient*length*change in Temperature

\DeltaL = \alpha L \DeltaT

.773 = coefficient*600*76.9

So anyways my theoretical calculations coefficient = 16.75*10^-6 / C

Copper's coefficient is 17*10^-6/ C

I took the percent difference 1.47% off of actual. Great.

Homework Equations




The Attempt at a Solution


I have no idea how to figure this out without the radius, circumference, or volume. Is it even possible?
 
Last edited:
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At some point - preferably before heating - you should have measured the diameter of the rod. If not, then you can only give a theoretical Δd, using variables. Diameter is a linear dimension. Thus, it will change according to the same rule as the length.
 
That's exactly what I was thinking, but neither my professor nor did the lab manual specify that. Oh actually, I just read the question again and it says : "Estimate" the change in diameter of the rod. Maybe it means I'm not suppose to actually calculate it but make a theoretical guess? Can I assume that the diameter increased equal to the length?
 
If, by "equal to length" you mean using the same equation, yes. Just change your "L"s to "d"s.
 
demonslayer42 said:
That's exactly what I was thinking, but neither my professor nor did the lab manual specify that. Oh actually, I just read the question again and it says : "Estimate" the change in diameter of the rod. Maybe it means I'm not suppose to actually calculate it but make a theoretical guess? Can I assume that the diameter increased equal to the length?
This is a fundamental concept in materials. The linear coefficient of thermal expansion applies to a direction (linear = in a line). If one measures the LCTE in one direction, then one can apply to the normal directions - assuming the material behaves isotropically. Some materials, e.g., hcp metals, are anisotropic.

The diameter is simply another linear dimension. p21bass describes it well.

If one didn't measure the diameter or volume, one could measure the mass, and using the density, determine the volume. From the volume and length, one can determine the area with reasonable certainty, and from area, one can determine diameter.
 

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