How does the change in diameter relate to the change in length?

Click For Summary

Homework Help Overview

The discussion revolves around the thermal expansion of a metal rod, specifically how the change in diameter relates to the change in length when the rod is heated. The original poster describes a lab experiment involving a copper rod and seeks to calculate the change in diameter based on given parameters such as initial and final temperatures, as well as the change in length.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate the change in diameter without having direct measurements of diameter, radius, or volume. Some participants suggest using theoretical approaches based on linear dimensions and the linear coefficient of thermal expansion. Others question the assumptions regarding the isotropic behavior of the material.

Discussion Status

Participants are exploring various interpretations of the problem, with some suggesting that the same principles used for length can be applied to diameter. There is an acknowledgment of the need for theoretical estimation rather than precise calculation, and guidance has been offered regarding the application of the linear coefficient of thermal expansion to different dimensions.

Contextual Notes

There is a mention of the lack of specific measurements for diameter or volume, which may limit the ability to calculate the change in diameter directly. The original poster also notes that the lab manual did not specify certain details, leading to some uncertainty about the expectations for the estimation of diameter change.

demonslayer42
Messages
18
Reaction score
0

Homework Statement



Find the change in diameter of the metal rod.

So I did a lab in class. We heated up a metal rod by putting it in a "jacket" and heating it with steam and it expanded. We were asked to calculate the liner coefficient. Well I did that just fine. I determine that the rod was copper. But how do I fined the change in diameter?

Length of Rod: 600mm

Temperature initial : 22.5 C
Temperature Final : 99.4 C
Change in Temperature :76.9 C

X initial: 5.849mm
X final 6.622mm
Change in length = .773mm

Change in Length = coefficient*length*change in Temperature

\DeltaL = \alpha L \DeltaT

.773 = coefficient*600*76.9

So anyways my theoretical calculations coefficient = 16.75*10^-6 / C

Copper's coefficient is 17*10^-6/ C

I took the percent difference 1.47% off of actual. Great.

Homework Equations




The Attempt at a Solution


I have no idea how to figure this out without the radius, circumference, or volume. Is it even possible?
 
Last edited:
Physics news on Phys.org
At some point - preferably before heating - you should have measured the diameter of the rod. If not, then you can only give a theoretical Δd, using variables. Diameter is a linear dimension. Thus, it will change according to the same rule as the length.
 
That's exactly what I was thinking, but neither my professor nor did the lab manual specify that. Oh actually, I just read the question again and it says : "Estimate" the change in diameter of the rod. Maybe it means I'm not suppose to actually calculate it but make a theoretical guess? Can I assume that the diameter increased equal to the length?
 
If, by "equal to length" you mean using the same equation, yes. Just change your "L"s to "d"s.
 
demonslayer42 said:
That's exactly what I was thinking, but neither my professor nor did the lab manual specify that. Oh actually, I just read the question again and it says : "Estimate" the change in diameter of the rod. Maybe it means I'm not suppose to actually calculate it but make a theoretical guess? Can I assume that the diameter increased equal to the length?
This is a fundamental concept in materials. The linear coefficient of thermal expansion applies to a direction (linear = in a line). If one measures the LCTE in one direction, then one can apply to the normal directions - assuming the material behaves isotropically. Some materials, e.g., hcp metals, are anisotropic.

The diameter is simply another linear dimension. p21bass describes it well.

If one didn't measure the diameter or volume, one could measure the mass, and using the density, determine the volume. From the volume and length, one can determine the area with reasonable certainty, and from area, one can determine diameter.
 

Similar threads

Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
6
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
24
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K