How Does the Limit Process Simplify the Expression x^2-36?

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Homework Help Overview

The discussion revolves around evaluating the limit of the expression \(\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}\) and its simplification, particularly in relation to the expression \(x^2-36\).

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various attempts to simplify the limit expression, including factoring and rationalizing. There are questions about the correctness of the approaches and the relevance of the expression \(x^2-36\) in the context of the limit.

Discussion Status

Some participants express uncertainty about their attempts while others suggest that the original approach is valid. There is an ongoing exploration of the limit process and its implications for the expression being analyzed.

Contextual Notes

Participants are considering the relationship between the limit expression and the polynomial \(x^2-36\), indicating a potential connection that may need further clarification.

fermio
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Homework Statement


\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}


Homework Equations



Answer is 1/6.

The Attempt at a Solution


\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}=\lim_{x\to 6}\frac{(x+3-9)(x+6)}{(x^2-36)(\sqrt{x+3}+3)}
 
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fermio said:

Homework Statement


\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}


Homework Equations



Answer is 1/6.

The Attempt at a Solution


\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}=\lim_{x\to 6}\frac{(x+3-9)(x+6)}{(x^2-36)(\sqrt{x+3}+3)}

Look more carefully at your attempt at a solution. You actually have it.
 
Do not bother with expanding with (x+6) as well:
\frac{\sqrt{x+3}-3}{(x-6)}=\frac{x+3-9}{(x-6)(\sqrt{x+3}+3)}=\frac{(x-6)}{(x-6)(\sqrt{x+3}+3)}
 
"Look more carefully at your attempt at a solution. You actually have it."
I don't see.
\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}=\lim_{x\to 6}\frac{(x+3-9)(x+6)}{(x^2-36)(\sqrt{x+3}+3)}=\lim_{x\to 6}\frac{x^2+6x-6x-36}{x^2\sqrt{x+3}+3x^2-36\sqrt{x+3}-108}

I get it.
\lim_{x\to 6}\frac{\sqrt{x+3}-3}{x-6}=\lim_{x\to 6}\frac{x+3-9}{(x-6)(\sqrt{x+3}+3)}=\lim_{x\to 6}\frac{1}{\sqrt{x+3}+3}=\frac{1}{6}
 
Last edited:
How can you write x^2-36?
 

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