How Does the Normalization of a Wave Function Work?

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sameh1
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hello

i attached my question if i can get some help

i think that there is another way to solve this problem
 
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  • Handwritten notes on lined paper working a wave function normalization: psi(phi) = 1 - sin phi, with integrals of cos m phi, sin m phi and products, then an attempt at N squared times the integral of (1 - sin phi) squared equal to 1, ending in N = 1/sqrt(3pi - 2) marked wrong.
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Your algebra is faulty.

[tex]\int_0^{2\pi}sin\phi d\phi=0[/tex]

Over a complete cycle for a sine (or cosine) you have as much positive area "under the curve" as you have negative.