How does the probability density function handle infinity in integrals?

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Homework Help Overview

The discussion revolves around the handling of integrals involving infinity, specifically in the context of probability density functions and their associated limits. The subject area includes calculus and integral evaluation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the process of evaluating integrals with infinite limits, questioning whether to take limits as the upper bound approaches infinity. There is also a clarification regarding the specific bounds of integration.

Discussion Status

Some participants have provided guidance on taking limits for integrals approaching infinity. There is an ongoing exploration of the implications of different bounds and the potential for divergence in certain cases.

Contextual Notes

There is a mention of confusion regarding the correct limits of integration, particularly distinguishing between different ranges such as x >= 1 and the implications for convergence or divergence of the integral.

converting1
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http://gyazo.com/02812d5d8f1d07c72153c9f66740e147

I've dealt with integrals with infinity before. When considering the part x >= 1 , do I take the limit as if it's a very large number? i.e. ## \int_0^{\infty} x^{-2.5} \ dx = 2/3 ## ?
 
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Yes, take the limit as the upper value goes to infinity.
 
converting1 said:
http://gyazo.com/02812d5d8f1d07c72153c9f66740e147

I've dealt with integrals with infinity before. When considering the part x >= 1 , do I take the limit as if it's a very large number? i.e. ## \int_0^{\infty} x^{-2.5} \ dx = 2/3 ## ?

You mean ##\int_1^\infty##. What you have written would diverge.
 
ok thank you
 

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