Beyond3D said:
I appreciate the effort, but could you explain it in simpler terms? I really don't have that much math knowledge, that is part of the reason I joined these forums.
You can find an easy phrasing of the Riemann hypothesis in this section:
https://www.physicsforums.com/insig...ans-sum/#Zeros-and-Poles-of-the-zeta-Function
All you need to know is that ##s=a+ib## is a complex number and ##\mathfrak{R}(s)=a## denotes its real part, and ##\Gamma(s)## denotes the generalization of ##\Gamma(n)=1\cdot 2\cdot 3\cdot \ldots\cdot (n-1)## to complex numbers by setting
\begin{align*}\dfrac{n!n^s}{s\cdot (s+1)\cdot \ldots\cdot (s+n)} \stackrel{n\to \infty }{\longrightarrow } \Gamma(s)\end{align*}
The connection to prime numbers is basically due to the formula
$$
\zeta(s)=\left(\dfrac{1}{1-\dfrac{1}{2^s}}\right)\cdot \left(\dfrac{1}{1-\dfrac{1}{3^s}}\right)\cdot \left(\dfrac{1}{1-\dfrac{1}{5^s}}\right)\cdot \left(\dfrac{1}{1-\dfrac{1}{7^s}}\right)\cdot\left(\dfrac{1}{1-\dfrac{1}{11^s}}\right)\cdots
$$
which runs over all prime numbers. Hence, the distribution of the prime numbers has a direct impact on the value of the Riemannian Zeta-function. However, the complex power ##{.}^s## complicates things so that ##\zeta(s)## can take the value ##0## which it does not if ##s## is real. This is because the product runs over all primes and is therefore a limit. That means, if the product gets smaller and smaller, the limit will be zero, even if the single factors are not. That's the same as in the sequence ##(1/2,1/3,1/4,1/5,1/6,\ldots)##. The single sequence members are positive, but their limit is zero since they get arbitrarily close to zero.
The Riemann hypothesis states that ##\zeta(a+ib)## has no zeros if ##1>a>1/2.## Now, the magic with the prime numbers is hidden in the equivalent formulation of this hypothesis that says: The Riemann hypothesis is true, if and only if the prime number counting function ##\pi(x)=\{\text{number of primes smaller than } x\}## is given by the formula ##\pi(x)= f(x)+C\cdot \sqrt{x}+r(x),## where ##f(x)## is a certain function, namely the so called integral logarithm, ##C## is some constant, and ##r(x)## an arbitrary small rest, an error term.
Of course, the work lies in the proof that those statements, the Riemann hypothesis and the distribution of primes, are equivalent. I have cited papers in which you can find this proof, but this requires mathematical techniques on a higher level, namely integration, and differentiation. See, e.g.,
https://www.claymath.org/wp-content/uploads/2023/04/Wilkins-translation.pdf, which basically follows Riemann's original paper
https://de.wikisource.org/wiki/Über_die_Anzahl_der_Primzahlen_unter_einer_gegebenen_Größe.
So your question can be rephrased as: Can you explain the eight pages of Riemann's paper about the distribution of prime numbers in simple words? The answer is yes, but it is not easy and certainly not short. Sciences are also always languages, i.e., a terminology that allows the description of complicated facts in short terms. Deassembling it into fundamental pieces is usually a mess, and the longer, the harder the problem is. And here, we have a hard (unsolved) problem whose formulation alone already takes higher mathematics. What you can take from that discussion is that Riemann's original work was about the prime number counting function, and the statement about the zeros of the zeta-function was a byproduct. This can be forgotten if we start at the other end with the Riemann hypothesis.