ThatGermanDude
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[SOLVED] Tension Equation Question
Hi, this is my first post here.
i came across an equation for tension in my textbook that i have never seen before and wanted to ask if someone could explain it to me.
Tension = g * (m[tex]^{1}[/tex] * m[tex]^{2}[/tex]) / (m[tex]^{1}[/tex] + m[tex]^{2}[/tex]) * (1 + sin[tex]\Theta[/tex])
i always thought Tension is equal to the sum of the forces applied to the rope.
the context is following problem:
a block of mass m[tex]_{1}[/tex] is at rest on an inclined plane at [tex]\Theta[/tex] degrees with the horizontal. it is connected with a block of mass m[tex]_{2}[/tex] that is hanging of the inclined plane hrough a massless rope.
so the way i thought about tension it would just be
Tension = m[tex]_{1}[/tex] * g * sin[tex]\Theta[/tex] + m[tex]_{2}[/tex] * g
but that gives me a different answer and i don't know what's wrong.
so any help is appreciated.
Hi, this is my first post here.
i came across an equation for tension in my textbook that i have never seen before and wanted to ask if someone could explain it to me.
Tension = g * (m[tex]^{1}[/tex] * m[tex]^{2}[/tex]) / (m[tex]^{1}[/tex] + m[tex]^{2}[/tex]) * (1 + sin[tex]\Theta[/tex])
i always thought Tension is equal to the sum of the forces applied to the rope.
the context is following problem:
a block of mass m[tex]_{1}[/tex] is at rest on an inclined plane at [tex]\Theta[/tex] degrees with the horizontal. it is connected with a block of mass m[tex]_{2}[/tex] that is hanging of the inclined plane hrough a massless rope.
so the way i thought about tension it would just be
Tension = m[tex]_{1}[/tex] * g * sin[tex]\Theta[/tex] + m[tex]_{2}[/tex] * g
but that gives me a different answer and i don't know what's wrong.
so any help is appreciated.
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