How Does the Tension Equation Differ with Inclined Planes and Multiple Masses?

  • Thread starter Thread starter ThatGermanDude
  • Start date Start date
  • Tags Tags
    Tension
Click For Summary

Homework Help Overview

The discussion revolves around understanding the tension in a rope connecting two masses, one on an inclined plane and the other hanging. The original poster presents a specific equation for tension and contrasts it with their own reasoning based on the forces acting on the masses.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to reconcile their understanding of tension with a new equation encountered in their textbook. They express confusion over differing results when applying their reasoning about forces acting on the masses.
  • Some participants suggest analyzing the forces acting on each mass and applying Newton's second law to clarify the tension calculation.
  • There are questions about the assumptions made regarding the forces involved, particularly the role of gravity versus acceleration.

Discussion Status

Participants are actively engaging in clarifying concepts related to tension and the forces acting on the masses. Some guidance has been offered regarding the need to analyze forces separately for each mass. The original poster indicates they have resolved their confusion, but the discussion remains open for further exploration of the concepts involved.

Contextual Notes

The problem involves a frictionless inclined plane and the dynamics of two connected masses, which may influence the assumptions about forces and tension in the rope.

ThatGermanDude
Messages
3
Reaction score
0
[SOLVED] Tension Equation Question

Hi, this is my first post here.

i came across an equation for tension in my textbook that i have never seen before and wanted to ask if someone could explain it to me.

Tension = g * (m[tex]^{1}[/tex] * m[tex]^{2}[/tex]) / (m[tex]^{1}[/tex] + m[tex]^{2}[/tex]) * (1 + sin[tex]\Theta[/tex])


i always thought Tension is equal to the sum of the forces applied to the rope.


the context is following problem:

a block of mass m[tex]_{1}[/tex] is at rest on an inclined plane at [tex]\Theta[/tex] degrees with the horizontal. it is connected with a block of mass m[tex]_{2}[/tex] that is hanging of the inclined plane hrough a massless rope.


so the way i thought about tension it would just be

Tension = m[tex]_{1}[/tex] * g * sin[tex]\Theta[/tex] + m[tex]_{2}[/tex] * g

but that gives me a different answer and i don't know what's wrong.

so any help is appreciated.
 
Last edited:
Physics news on Phys.org
ThatGermanDude said:
i always thought Tension is equal to the sum of the forces applied to the rope.
The tension is the force exerted on each end of the rope (and exerted by each end of the rope). Note that for a massless rope, the force at each end is the same--the tension is the same throughout the rope.

so the way i thought about tension it would just be

Tension = m[tex]_{1}[/tex] * g * sin[tex]\Theta[/tex] + m[tex]_{2}[/tex] * g
Realize the the weights are forces that act directly on the masses, not the rope. To find the tension in the rope, analyze the forces on each mass: On m1 there is gravity and the rope tension; on m2 there is also gravity and rope tension. Apply Newton's 2nd law to each mass and solve for the tension.
 
Draw a force diagram for the two blocks with the blocks having an acceleration 'a' and a tension 'T'. Then actually solve for T and a. Assuming it's the sum of the two gravitational forces is just jumping to conclusions.
 
i did all that and then end up with the equation i stated before.
in this case the only acting forces are th weights since the slope is frictionless.
 
Specify the forces acting on each mass and the resulting equations you got from applying Newton's 2nd law.
 
i figured it out. the mistake i made was using gravity instead of acceleration, like i should have, to find tension.

thanks
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
7K
Replies
46
Views
7K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
5K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K