How Does Voltage Variation Affect Power in a 100-W Heater?

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Homework Help Overview

The discussion revolves around a 100-W heater designed to operate at 120V, focusing on how variations in voltage affect power output. Participants are exploring the relationship between voltage, resistance, and power, particularly through the lens of differential changes in voltage and power.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the heater's resistance and current, while also exploring the implications of voltage changes on power output. There is a focus on using differential approximations to understand these relationships.

Discussion Status

Some participants have provided hints regarding the use of derivatives to approximate changes in power with respect to voltage. Questions about the constancy of resistance and current during voltage changes have been raised, indicating a productive exploration of underlying assumptions.

Contextual Notes

There is a hint that the resistance of the heater is assumed to be constant, despite changes in voltage, which is a point of discussion among participants. The original poster expresses uncertainty about the relationships and calculations involved in the problem.

LeakyFrog
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Homework Statement


A 100-W heater is designed to operate with an applied
voltage of 120V.

a) What is the heater's resistance, and what current does the heater carry?

b) Show that if the potential difference V across the heater changes by a small
amount ΔV, the power P changes by a small amount ΔP, where ΔP/P = 2ΔV/V. (Hint:
Approximate the changes by modeling them as differentials, and assume the
resistance is constant.

c) Using the part b result, find the approximate power delivered to the heater
if the potential difference is decreased to 115V. Compare your result to the
exact answer.


Homework Equations


P = IV = V2/R

The Attempt at a Solution


I'm stuck on part b). So far I have
ΔP=ΔV2/R

ΔP/P=(ΔV/V)2

I'm not really sure what to do.
 
Physics news on Phys.org
The change of a function f(x) can be approximated by Δf=f'(x)Δx, where f' is the derivative of f(x) taken at the original value of x, and Δx is a small change of x.


ehild
 
Thanks.

Another question, for part c) when you change the voltage on a circuit does the resistance stay the same? Or the current? Although I don't really see how the current could but maybe i suppose.
 
The heater stays the same, isn't it? And it consist of a resistor, and some other parts which do not change either, if you plug it into an other socket or the household voltage decreases because of some overload happening in the network.
Question c. wants you to apply the formula in question b, if V and ΔV are given.

ehild
 

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