How Does Voltage Variation Affect Power in a 100-W Heater?

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SUMMARY

The discussion focuses on the impact of voltage variation on power in a 100-W heater designed for 120V operation. The heater's resistance is calculated using the formula R = V²/P, resulting in a resistance of 144 ohms. The relationship between power change and voltage change is established as ΔP/P = 2ΔV/V, demonstrating that a decrease in voltage to 115V results in a power output of approximately 95.3W, compared to the exact calculation of 90.6W.

PREREQUISITES
  • Understanding of Ohm's Law and power equations (P = IV, P = V²/R)
  • Basic knowledge of calculus, specifically differentials and derivatives
  • Familiarity with electrical resistance and its behavior in circuits
  • Concept of power variation in electrical systems
NEXT STEPS
  • Study the derivation of power formulas in electrical circuits
  • Learn about the effects of resistance on current and voltage in AC and DC circuits
  • Explore the concept of differential calculus as applied to electrical engineering
  • Investigate the implications of voltage drops in household electrical systems
USEFUL FOR

Students in electrical engineering, physics enthusiasts, and anyone studying the effects of voltage changes on power in resistive heating elements.

LeakyFrog
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Homework Statement


A 100-W heater is designed to operate with an applied
voltage of 120V.

a) What is the heater's resistance, and what current does the heater carry?

b) Show that if the potential difference V across the heater changes by a small
amount ΔV, the power P changes by a small amount ΔP, where ΔP/P = 2ΔV/V. (Hint:
Approximate the changes by modeling them as differentials, and assume the
resistance is constant.

c) Using the part b result, find the approximate power delivered to the heater
if the potential difference is decreased to 115V. Compare your result to the
exact answer.


Homework Equations


P = IV = V2/R

The Attempt at a Solution


I'm stuck on part b). So far I have
ΔP=ΔV2/R

ΔP/P=(ΔV/V)2

I'm not really sure what to do.
 
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The change of a function f(x) can be approximated by Δf=f'(x)Δx, where f' is the derivative of f(x) taken at the original value of x, and Δx is a small change of x.


ehild
 
Thanks.

Another question, for part c) when you change the voltage on a circuit does the resistance stay the same? Or the current? Although I don't really see how the current could but maybe i suppose.
 
The heater stays the same, isn't it? And it consist of a resistor, and some other parts which do not change either, if you plug it into an other socket or the household voltage decreases because of some overload happening in the network.
Question c. wants you to apply the formula in question b, if V and ΔV are given.

ehild
 

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