How Does Wind Speed Affect Roof Pressure in a Storm?

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SUMMARY

The discussion focuses on calculating the pressure difference created by wind speed on a roof during a storm, specifically with a roof area of 92.8 m² and wind speed of 106.8 km/hr. Using the air density of 1.25 kg/m³, the pressure difference is derived from the equation involving pressure, area, and wind speed, resulting in a value of 3.91 atm*s. The conversation also references Bernoulli's principle, indicating its relevance in understanding fluid dynamics in this context.

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  • Understanding of fluid dynamics principles, particularly Bernoulli's equation.
  • Knowledge of pressure calculations in physics.
  • Familiarity with unit conversions, specifically between km/hr and m/s.
  • Basic grasp of atmospheric pressure and its measurement units.
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  • Learn about pressure calculations in various contexts, including atmospheric and hydrostatic pressure.
  • Research the effects of wind speed on structural integrity and design considerations for roofs.
  • Explore advanced fluid dynamics simulations using software like ANSYS Fluent or OpenFOAM.
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Engineers, architects, meteorologists, and students studying physics or civil engineering who are interested in the impact of wind on structures and pressure dynamics.

Rikin25
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Homework Statement



The roof of a house has an area of 92.8 m^2. In a violent storm the air blows across the roof at a speed of 106.8 km/hr.

Homework Equations



Assuming that the air has a density of 1.25 kg/m^3, what pressure difference is created by the storm between the air outside and inside the house?

The Attempt at a Solution



Pressure/s = Area * density / speed (m/s)
= 92.8 * 1.25 / (106.8/3.6)
= 3.91 atm*s

how do i find the time?
or am i doing the whole thing wrong?
 
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Maybe this has something to do with the Bernoulli's principle:

\frac{\rho v^{2}}{2}+\rho g h + p = const.

But then you don't need the surface...
 

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