russ_watters said:
The air provides its own boundary in low-speed flow when it is essentially incompressible. The velocity increase/pressure drop happens because it is being "squeezed", just like in a venturi. This is similar to the principle behind an aerospike engine, where air pressure helps constrain the flow:
http://en.wikipedia.org/wiki/Aerospike_engine
The fact that it is incompressible makes it less likely to "provide its own boundary," which does not accurately reflect what actually occurs. The velocity increase happens because he design of the trailing edge sets a certain separation point and the conservation laws then require the velocity to increase greatly over the upper surface to maintain physical equilibrium. For an explanation of why the Venturi approach is wrong, see this link:
https://www.grc.nasa.gov/www/k-12/airplane/wrong3.html
Also, that is not how an aerospike engine works. Aerospikes are, first and foremost, compressible flow devices and the Venturi effect is irrelevant to the phenomenon. The constraint by the outer atmosphere here (and importantly, variable constraint) is due to some of the unique features of compressible flows.
russ_watters said:
I'm aware they can't be completely decoupled. Nevertheless, it is typical for the top surface to produce more of the lift
So which is it? You can believe both things.
The shape of the top certainly contributes to lift. You cannot measure lift an just the top surface, though. The top definitely plays a role, but it does so as a part of the whole shape.
russ_watters said:
That isn't true. Both the top and bottom surface have pressure profiles that are measured/expressed as gauge pressure because the default is atmospheric pressure. As a result, the pressure on the top surface is measured to be negative. For a simplified/idealized example, a flat-bottom airfoil with the bottom parallel to the airflow would essentially just have atmospheric pressure below it and all of the lift generated by the top surface. Here's a sample graph of a pressure profile (not a flat bottom but still showing more of the lift derived from the top surface):
http://www.wfis.uni.lodz.pl/edu/Proposal/image093.gif
First, I know what gauge pressure is. In fact, I typically would give zero points if a student uses gauge pressure where absolute pressure is required because it's that important to keep straight.
Second, plotted there is the pressure coefficient, the definition of which includes a numerator that is equivalent to gauge pressure, so in that, you are correct. That is where it ends. Just because the pressure coefficient is negative does not mean there is somehow negative pressure on the upper surface. The force on a given surface due to pressure is
always dependent on the absolute pressure, not gauge pressure, and absolute pressure is always positive. The pressure on the upper surface is always downward. A more negative pressure coefficient just means there is less downward force on the top to counteract the larger pressure on the bottom.
Third, a flat-bottomed airfoil would not necessarily have atmospheric pressure on its underside. This would generally only be true if the leading and train edges were sharp in a way such that the bottom approximated a flat plate, otherwise the curvature of the leading edge would accelerate the flow.
Even if the bottom is atmospheric, the total lift force is still the integrated sum of the absolute pressure on the bottom minus that on the top. The force due to the pressure on the top is still downward. The importance of the upper surface contour is therefore effectively to make the force on the upper surface
less downward for a given upward force on the bottom. This is what I mean by being unable to decouple the two.