How Far Does a Car Travel Accelerating Uniformly from Rest to 20 m/s West?

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SUMMARY

A car accelerating uniformly from rest at 2.50 m/s² west reaches a velocity of 20.0 m/s west after 3.2 seconds. The displacement during this time is calculated using the formula xf = 1/2(vf + vi)t, resulting in a total distance of 32 meters west. The calculations confirm that the time taken to reach the final velocity is indeed 3.2 seconds, validating the use of kinematic equations in this scenario.

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kselanders
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Homework Statement



A car accelerates uniformly from rest. If the acceleration was 2.50 m/s^2 west, what was its displacement when it reached a velocity of 20.0 m/s west?

Homework Equations


The Attempt at a Solution



A= 2.50 m/s^2 west
Vi= 0 m/s
Vf= 20 m/s west

vf=vi+at
20m/s=2.50m/s^2(t)
20m/s/2.50m/s^2=t
t=3.2sxf=xi+1/2(vf+vi)t
xf=1/2(20m/s)(3.2s)
xf=(10m/s)(3.2s)
xf=32m
 
Last edited:
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Hi kselanders, welcome to PF.
vf=vi+at
20m/s=2.50m/s^2(t)
20m/s/2.50m/s^2=t
t=3.2s

Check this calculation.
 

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