How Far Does a Rolling Coin Travel Before Stopping?

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SUMMARY

The discussion focuses on calculating the distance a coin with a diameter of 1.50 cm rolls before stopping, given an initial angular speed of 13.4 rad/s and an angular acceleration of -2.03 rad/s². The relevant equation used is wf² = wi² + 2a(dTheta), where dTheta is the angular displacement in radians. The participants clarify that the diameter is crucial for determining the linear distance traveled, as it relates to the coin's circumference and the conversion from radians to meters.

PREREQUISITES
  • Understanding of angular motion equations, specifically wf² = wi² + 2a(dTheta)
  • Knowledge of the relationship between linear distance and angular displacement
  • Familiarity with the concept of circumference and its calculation
  • Basic grasp of angular acceleration and its effects on motion
NEXT STEPS
  • Calculate the linear distance using the coin's circumference and angular displacement
  • Explore the relationship between radians and linear distance in rolling motion
  • Study the effects of angular acceleration on rolling objects
  • Investigate practical applications of angular motion equations in real-world scenarios
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of rolling motion and angular kinematics.

Leid_X09
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A coin with a diameter of 1.50 cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular speed of 13.4 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular acceleration of magnitude 2.03 rad/s2, how far does the coin roll before coming to rest?


I know that wf^2 = wi^2 + 2a(dTheta) should be used, and I find theta to be 44.2 but the 44.2 is in rads, so how do i translate this into ms? What does the 1.50 diameter have to do with this problem?
 
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Leid_X09 said:
A coin with a diameter of 1.50 cm is dropped on edge onto a horizontal surface. The coin starts out with an initial angular speed of 13.4 rad/s and rolls in a straight line without slipping. If the rotation slows with an angular acceleration of magnitude 2.03 rad/s2, how far does the coin roll before coming to rest?


I know that wf^2 = wi^2 + 2a(dTheta) should be used, and I find theta to be 44.2 but the 44.2 is in rads, so how do i translate this into ms? What does the 1.50 diameter have to do with this problem?

How many radians to one revolution?

What distance is that? Maybe think circumference plays a part?
 

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