How Far Does the Goalie Slide on Ice After Catching a Hockey Puck?

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A hockey player sends a .4kg puck at 80 m/s. A stationary golie cathces the puck. If the coefficient of friction of the golie on the ice is .05 and his mass is 90 kg how far does he slide on the ice before he comes to a stop.

I have found
normal force = mg
= 885.92N
and then friction = .05(885.92N)
= 44.296N
and using conservation of momentum i found the velocity after the collision will be 0.35m/s
but now I am stuck
please help.

 

[tiny-tim]

Welcome to PF!

Hi Loading! Welcome to PF!

… using conservation of momentum i found the velocity after the collision will be 0.35m/s
but now I am stuck

find the acceleration (btw, you didn't need to find the actual force ) …

then, since you know the initial and final velocities, you can use one of the standard constant acceleration equations to find the distance

 

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okay so this is what i have upto now:
mass of puck = .4kg
Speed of puck = 80m/s
Mass of goalie= 90kg and he is at rest
μ = 0.05

i found the common velocity after the colision to be 0.35 m/s
due to vertical equilibrium i stated that Fg=Fn
Fn=mg
Fn=885.92N
and then Friction = μ x Fn
Friction = 44.296N

but i can't seem to find the acceleration. do i use the friction equation to find it...that will just give me 9.8m/s2

 

[tiny-tim]

Hi Loading!

but i can't seem to find the acceleration …

uhh?

just do what good ol' Newton would have done …

divide the force by the mass! ​

 

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ooh :D thanks dude

 

[tiny-tim]

you have probably noticed that the acceleration is -µg …

can you prove this? ​

(you need to: it will save you time in the exam )

 

[TSny]

tiny-tim, you need to upgrade your avatar.