What is the final velocity of the goalie after catching a hockey puck?

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SUMMARY

The final velocity of a goalie after catching a hockey puck can be calculated using the principle of conservation of momentum. In this scenario, a 0.105-kg hockey puck moving at 20 m/s is caught by a 77-kg goalie at rest. The equation m1v1 + m2v2 = (m1 + m2)v' is applied, where m1 is the mass of the puck, v1 is its initial velocity, m2 is the mass of the goalie, and v2 is the initial velocity of the goalie. The final velocity (v') of the goalie sliding on the ice is determined to be 2.0 m/s.

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Homework Statement



A 0.105-kg hockey puck moving at 20 m/s is caught and held by a 77-kg goalie at rest. With what speed does the goalie slide on the ice?


Homework Equations



(Initial puck speed)(Puck mass)
= (combined mass)*(final goalie velocity)

The Attempt at a Solution


(0)(0.105)=(77.105)(20)
= 1542.1 m/s
 
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wesDOT is correct. Initial velocity of the puck should not be zero.

To cross-post from the other thread about two cars colliding inelastically:

Re: Two objects colliding & sticking together said:
The main thing you can use in the problem is conservation of momentum:

m1v1+m2v2=(m1+m2)v'

This equality is a result of the completely inelastic collision. The question asks you to solve for v'.

m1 : mass of the puck
v1 : initial velocity of the puck
m2 : mass of the goalie
v2 : initial velocity of the goalie
v' : final velocity of the puck+goalie

Hope this helped.
 
oops, double posted. sorry. & that was correct, thanks!
 

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