How Far from a Conductor Is a Magnetic Field of 3.1x10^-5T?

Click For Summary
SUMMARY

The discussion focuses on calculating the distance from a long conductor carrying a current of 12.5A where the magnetic field strength is 3.1x10^-5T. The formula used is B = μI / (2πr), leading to the rearranged equation r = μI / (2πB). The calculation reveals that the distance r is approximately 8.1x10^5 meters, with the permeability constant μ being incorrectly stated as 4π. The correct value for μ should be clarified for accurate results.

PREREQUISITES
  • Understanding of Ampère's Law
  • Familiarity with magnetic field calculations
  • Knowledge of the permeability of free space (μ)
  • Basic algebra for rearranging equations
NEXT STEPS
  • Review the correct value of the permeability of free space (μ) in magnetic field calculations
  • Study the derivation of the magnetic field around a long straight conductor
  • Explore applications of Ampère's Law in different geometries
  • Investigate the effects of varying current on magnetic field strength
USEFUL FOR

Physics students, electrical engineers, and anyone interested in electromagnetic theory and applications of Ampère's Law.

jalen
Messages
25
Reaction score
0

Homework Statement



12.5A, 3.1x10^-5

Homework Equations



How far from a long conductor passing a current of 12.5A is the magentic field of strength 3.1x10^-5T?

The Attempt at a Solution



B= uI/2(pi)r

r=uI/2(pi)B
=(4pi)(12.5A)/ 2(pi)(3.1x10^-5T)
= 8.1x10^5m
 
Physics news on Phys.org
u_0 isn't 4 pi.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
Replies
3
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
10
Views
2K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 23 ·
Replies
23
Views
6K