How far have u gone on the stationary bike?

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The discussion centers on calculating the distance traveled on a stationary bike given an angular speed of 10.4 rad/s and a wheel radius of 0.507 m over a duration of 42.6 minutes. The user initially calculated the angular displacement as 13291.2 radians using the equation θ = 1/2 (ω0 + ω)t. The correct approach involves using the relationship between angular speed (ω), tangential velocity (v), and radius (R) to find the distance traveled, confirming that distance equals velocity multiplied by time.

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Suppose you are riding a stationary exercise bicycle, and the electronic meter indicates that the wheel is rotating at 10.4 rad/s. The wheel has a radius of 0.507 m. If you ride the bike for 42.6 min, how far would you have gone if the bike could move?

ok here is what i know

my W (angular speed) is 10.4 rad//s
Radius = 0.507 m
time = 42.6 min x 60 sec = 2556 sec

I tried to use this equation

theta = 1/2 (w0 + w )t and I got a value of 13291.2 radians can I use this value to find the distance, or am I doing something wrong?

Thanks
 
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shaka23h said:
Suppose you are riding a stationary exercise bicycle, and the electronic meter indicates that the wheel is rotating at 10.4 rad/s. The wheel has a radius of 0.507 m. If you ride the bike for 42.6 min, how far would you have gone if the bike could move?

ok here is what i know

my W (angular speed) is 10.4 rad//s
Radius = 0.507 m
time = 42.6 min x 60 sec = 2556 sec

I tried to use this equation

theta = 1/2 (w0 + w )t and I got a value of 13291.2 radians can I use this value to find the distance, or am I doing something wrong?

Thanks
You have to the relationship between the angular speed and tangential velocity. If you assume that there is no slippage between the wheel and the road, then velocity x time = distance. Do you know how \omega is related to v and R?

AM
 
ya I figured it out.

Thanks a lot
 

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