How Far is the Second Object from the Convex Mirror?

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SUMMARY

The discussion centers on determining the distance of a second object from a convex mirror, given that the first object is 14 cm in front of the mirror and produces an image 7 cm behind it. The second object is twice as tall as the first, yet its image height remains the same, indicating a magnification ratio of 1/4. By applying the mirror equation and the magnification formula, participants conclude that the second object's distance from the mirror can be calculated by substituting the image distance into the mirror formula.

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  • Understanding of the mirror equation for convex mirrors
  • Knowledge of magnification concepts in optics
  • Familiarity with the properties of convex mirrors
  • Basic algebra skills for solving equations
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lizzyann31
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Homework Statement


An object is located 14 cm in front of a convex mirror, the image being 7 cm behind the mirror. A second object, twice as tall as the first one, is placed in front of the mirror, but at a different location. The image of this second object has the same height as the other image. How far in front of the mirror is the second object located?


I know I need to use the mirror equation... but I am totally LOST!
 
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First of all find the focal length of the convex mirror and magnification. In this problem magnification v/u = 1/2 = I/o. When the When the size of the object doubles keepin image height the same. magnification becomes 1/4.
So V'/U' = 1/4. Write V' in terms of U', substitute in the mirror formula to get U'
 

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