How Can a Convex Mirror Project a Real Image?

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SUMMARY

The discussion centers on the use of a convex mirror to project a real image that is five times taller than the object. Participants clarify that a convex mirror cannot produce a real image; instead, it forms virtual images. The correct type of mirror for achieving a real image is a concave mirror, and the object must be positioned between the focal point and the mirror to achieve the desired magnification. The mathematical relationships governing these optics include the magnification formula M = (Di)/(Do) and the mirror equation 1/(Di) + 1/(Do) = 1/(F).

PREREQUISITES
  • Understanding of spherical mirrors, specifically concave and convex mirrors.
  • Familiarity with optical principles, including image formation and magnification.
  • Knowledge of the mirror equation and magnification formulas.
  • Basic concepts of real versus virtual images in optics.
NEXT STEPS
  • Study the properties of concave mirrors and their applications in image formation.
  • Learn about the derivation and application of the mirror equation in optics.
  • Explore practical experiments demonstrating real and virtual images using different types of mirrors.
  • Investigate the concept of magnification in various optical devices, including cameras and telescopes.
USEFUL FOR

Students of physics, optical engineers, and educators looking to deepen their understanding of mirror optics and image formation principles.

kmr159
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1. A spherical mirror is used to form an image 5 times as tall as an object, on a screen positioned 5.0m from the mirror.
a) Describe the type of mirror required
b) Where should the mirror be positioned relative to the object




2. M = (Di)/(Do) & 1/(Di) + 1/(Do) = 1/(F)



3. I have solved the problem ( assuming Di = -5) getting Do = 1. m & the mirror being a convex mirror. However how it possible for a virtual image to be projected onto a screen? Thanks
 
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A virtual image cannot be projected onto a screen. Is there a way to get a real image 5 times taller than the object? (The problem does not say that the image must be upright. The image might be inverted.)
 
kmr159 said:
3. I have solved the problem ( assuming Di = -5) getting Do = 1. m & the mirror being a convex mirror. However how it possible for a virtual image to be projected onto a screen? Thanks

It is not virtual. What type of shpherical mirror produces a real image? Between what two positions on the axis should the object be to get an enlarged real image?
 

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