How Far Should Rondo Compress the Spring to Hit the Target?

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SUMMARY

The discussion centers on calculating the necessary compression of a spring in a spring-loaded gun to hit a target. Bobby compresses the spring 1.1 cm, resulting in the marble falling 0.27 m short of the target located 2.20 m away. The key principle involved is the conversion of spring potential energy into kinetic energy, which is essential for determining the required compression for Rondo to achieve a direct hit. Understanding this energy conversion is crucial for solving similar projectile motion problems.

PREREQUISITES
  • Understanding of spring potential energy and its formula
  • Knowledge of kinetic energy and its relationship to motion
  • Familiarity with basic physics concepts of projectile motion
  • Ability to apply energy conservation principles in physics
NEXT STEPS
  • Study the formula for spring potential energy: PE = 1/2 kx²
  • Learn about the conservation of mechanical energy in projectile motion
  • Explore the effects of different spring constants on projectile distance
  • Practice solving similar problems involving energy conversion in mechanics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of energy conversion in mechanical systems, particularly in projectile motion scenarios.

bballcool34
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Here's the question:

Two children are playing a game in which they try to hit a small box on the floor with a marble fired from a spring-loaded gun that is mounted on a table. The target box is horizontal distance D = 2.20 m from the edge of the table. Bobby compresses the spring 1.1 cm, but the center of the marble falls .27 m short of the center of the box. How far should Rondo compress the spring to score a direct hit? (assume that neither spring nor ball encounters friction).

I know the general gist of how to solve the problem---Find spring potential energy of Bobby, set that equal to K, and do the same for Rhonda. However, I don't understand WHY I'm supposed to do this. Why does spring potential energy = KE in this problem? If anyone could explain it to me, that'd be great:
 
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If you are ignoring frictional effects, then the only other energy conversion taking is place is the conversion of the potential energy to kinetic. If that did not happen, then after the spring is released the ball would not move now would it?
 

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