An amount of work equal to 1.5 J is required to compress the spring in a spring gun. ?
Wtotal = change of KE[/B]
The Attempt at a Solution
W=ΔKE=(1/2)m(Vf² - Vi²)
It sounds like the Vf >0 and would be maximum after the spring is compressed hard and get ready to launch the marble. Hence, the marble will have the maximum launch speed. In that case, Vi of marble = Vf of the spring.
Vi of the spring should be zero. It starts from rest before compression.
But how is the Vi and Vf of the spring help me find the "launch Speed " of the marble?
I may not understand the process of energy transfer and force interaction between the marble and spring. Quite confusing!
I am lost and am unsure where my reasoning is wrong. Need help!