How Far Will a Rock Travel Horizontally from a Volcano When Ejected at an Angle?

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SUMMARY

The discussion focuses on calculating the horizontal distance a rock will travel when ejected from a volcano at a specific angle. The maximum height reached by rocks ejected from a 1750 m high volcano at a speed of 170 m/s is determined to be 3.22 x 10^3 m. For a rock ejected at a 30-degree angle, participants are advised to separate the x and y components of motion, using the equations of projectile motion to find the time of flight and horizontal distance. Common errors include incorrect time calculations and misunderstanding the signs of initial velocity and acceleration.

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SilentBlade91
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1. I got the first part right but I cannot figure out how to do the second part! Help please! And thank you!

Volcanoes on the Earth eject rocks at speeds of up to 170 m/s. Consider a 1750 m high volcano which ejects rocks in all directions. What is the maximum height above sea level reached by rocks?
Answer: 3.22*10^3m

part B: Consider a rock ejected an angle of 30degrees. How far from the axis of the volcano (horizontally) will it strike the ocean?
 
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separate your x and y components

x:
v0x=170cos30
x=?
t= from y

y:
v0y =170sin30
a =-9.81m/s^2
y = -1750m
t =
solve for t using y=v0*t+(1/2)at^2
then plug t into your x component to get x

(make sure to keep your initial y velocity positive and your acceleration and y distance negative)
 
Hi, Iam currently working on a similar problem and I keep getting it wrong. I found t to equal 17.34s or 3.57s by using the quadratic formula i then took a time and plugged it back into the formula using all the x component numbers and got 2429.14m or 4084.41m both are wrong.

my volcano is 2000m high and rocks are shooting at 45 degree angle traveling at 170m/s.
thanks
 

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