How Fast Can a Trebuchet Fling a Light Object?

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SUMMARY

The discussion focuses on calculating the maximum speed of a lighter object (0.120 kg) flung by a trebuchet, modeled as a stiff rod of negligible mass (3.00 m) with a larger mass (60.0 kg) at one end. The system operates on a frictionless axle located 14.0 cm from the larger mass. The moment of inertia (I_cm) is calculated as 20.25 kg*m², and the kinetic energy equation K = 1/2 I_cm w² + 1/2 M v_cm² is utilized to derive the maximum speed of the lighter object. Participants express uncertainty in modeling the system and seek guidance on the next steps in their calculations.

PREREQUISITES
  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with kinetic energy equations in physics
  • Basic knowledge of trebuchet mechanics
  • Ability to perform calculations involving mass and distance in a physics context
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  • Learn about the conservation of energy in mechanical systems
  • Explore the dynamics of trebuchet design and optimization
  • Investigate the effects of mass distribution on projectile motion
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Physics students, engineering enthusiasts, and anyone interested in the mechanics of medieval siege engines and projectile motion calculations.

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Homework Statement


A war-wolf, or trebuchet, is a device used during the Middle Ages to throw rocks at castles and now sometimes used to fling pumpkins and pianos. A simple trebuchet is shown in Figure P8.77. Model it as a stiff rod of negligible mass 3.00 m long and joining particles of mass 60.0 kg and 0.120 kg at its ends. It can turn on a frictionless horizontal axle perpendicular to the rod and 14.0 cm from the particle of larger mass. The rod is released from rest in a horizontal orientation. Find the maximum speed that the object of smaller mass attains.
Pic: www.s-consolidated.com/graphics/trebuchet.jpg[/URL]

[h2]Homework Equations[/h2]
[tex]K = \frac{1}{2} I_{cm} w^2 + \frac{1}{2} M v_{cm}^2[/tex]


[h2]The Attempt at a Solution[/h2]

I am not even sure how to model it yet. I will attempt some things and write them as I go.
 
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I_{cm} = (M + m) * l^2/12where M is the 60kg, m is the 0.12kg and l is 3mI_{cm} = 20.25 kg*m^2v_{cm} = (M + m)*v/(M + m)v_{cm} = vK = \frac{1}{2} I_{cm} w^2 + \frac{1}{2} M v_{cm}^2 K = \frac{1}{2} * 20.25 * w^2 + \frac{1}{2} * 60 * v^2I am not sure where to go from here.
 

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