How Fast Does a Ball Shoot from a Toy Cannon with Friction?

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SUMMARY

The discussion focuses on calculating the exit speed of a 5.30 g soft rubber ball from a toy cannon, which utilizes a spring with a force constant of 9.00 N/m. The spring is compressed by 5.00 cm, and the ball travels 16.0 cm in the barrel while experiencing a constant frictional force of 0.0320 N. The initial calculation of the speed yielded an incorrect result, prompting a suggestion to adjust the distance over which friction acts from 0.11 m to 0.16 m for accurate results. The correct speed of the projectile is determined to be 1.7079 m/s.

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  • Basic understanding of friction and its effects on motion
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A toy cannon uses a spring to project a 5.30 g soft rubber ball. The spring is originally compressed by 5.00 cm and has a force constant of 9.00 N/m. When it is fired, the ball moves 16.0 cm through the horizontal barrel of the cannon, and a constant frictional force of 0.0320 N exists between barrel and ball.

(a) With what speed does the projectile leave the barrel of the cannon?

Wnet = \DeltaKE
Ws - Wfk = .5mv2 - 0
.5kx2 - fkd = .5mv2
.5(9)(.052) - (.032)(.11) = .5(.0053)v2
v = 1.7079

Final answer is incorrect. Any ideas?
 
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Have you tried replacing .11 with .16? Friction acts over full length of barrel. What is the answer?
 

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