How fast is an ocean wave with given displacement and time function?

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Homework Help Overview

The problem involves determining the speed of an ocean wave based on its vertical displacement function, which is expressed in terms of position and time. The context is within the study of wave mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of wave speed and its relation to the wave function provided. There is an exploration of the distinction between the vertical velocity of the wave surface and the horizontal speed of wave propagation. Questions arise regarding the interpretation of parameters such as amplitude, wave number, and angular frequency from the given function.

Discussion Status

The discussion is active, with participants clarifying concepts related to wave speed and the parameters derived from the wave function. Some guidance has been offered regarding the relationship between angular frequency and wave speed, indicating a productive direction in understanding the problem.

Contextual Notes

Participants are navigating the definitions and relationships between different wave properties, including the distinction between vertical movement and wave propagation speed. There is an acknowledgment of potential confusion regarding the derivative of the wave function.

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Homework Statement



Find the speed of an ocean wave whose vertical displacement y as a function of time t is given by y(x,t) = 3.7 cos(2.2x - 5.6t), where all quantities are in SI units.


Homework Equations



v=-ωAsin(kx-ωt)


The Attempt at a Solution



I'm really not at all sure where to begin with this one. I'm not even sure if my derivative equation is correct...

Any direction at all would be much appreciated! Thank you!
 
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have you been introduced to the definition of "wave speed"?
 
I believe so. The wave speed is the speed at which the disturbance propagates throughout the medium...v=λf. So that's the equation I need instead?

In that case, when you take the derivative of position and are given a velocity function, what exactly is that the velocity of? The speed something travels along the wave?
 
Your function y(x,t) tells you the height of the free surface at each position and time. By taking the derivative dy/dt, you've found the (vertical) velocity of the surface as it heaves up and down, but that isn't the same thing as the speed the wave crests move horizontally as they propagate. For that you need to look carefully at the definition v=λf. What can you tell about λ and f from your original expression: y(x,t) = 3.7 cos(2.2x - 5.6t) ?
 
Hm, I believe it gives me my amplitude, k, and angular frequency?
 
Aha! I got it! Since it gives us k and omega, we simply use the relation omega=2*pi*f and k=(2*pi)/lambda. And then substituting in for v=f*lambda gives us our answer.

I need to keep my wave speed vs. velocity of vertical movement straight...

Thank you so much!
 
You're welcome! \o/
 

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