- #1

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I've gotten the other parts of the question right, so I know that:

ω = 125.66 rad/s

A = 2.50 * 10

^{-3}m

k = 3.49 rad/m

The wave is moving in the +x direction.

The general equation for the position of a particle on the wave is:

y(x,t) = Acos(kx - ωt)

So this means (please correct me if I'm wrong) that the transverse velocity of a particle on the wave is:

V

_{y}(x,t) = ωAsin(kx - ωt) = (125.66)((2.50 * 10

^{-3}m)sin(3.49x - 125.66t)

I'm asked to find V

_{y}at x = 1.35m, t = 0.0625s.

For this I got 2.07*10

^{-4}m/s, but I'm told this is incorrect. Where am I going wrong?