How Fast Will a Charged Sphere Move Along the Axis of a Ring Charge?

Click For Summary
SUMMARY

The discussion centers on calculating the velocity of an 8.2 g charged sphere with a charge of 2.4 microC as it moves along the axis of a 13.4 cm radius ring that carries a uniformly distributed charge of 14.8 microC. The electric field produced by the ring can be treated as that of a point charge, allowing the use of the formula e = kq/r. The kinetic energy of the sphere can be determined using (1/2)mv^2 = e, leading to a calculated velocity of 4248 m/s when the sphere is 1.8 m from the center of the ring. The symmetry of the ring simplifies the analysis of the electric field along the x-axis.

PREREQUISITES
  • Understanding of electrostatics, specifically Coulomb's law
  • Familiarity with the concept of electric fields and potential energy
  • Knowledge of kinetic energy equations in physics
  • Ability to apply symmetry in electric field calculations
NEXT STEPS
  • Study the derivation of electric fields from point charges
  • Learn about the motion of charged particles in electric fields
  • Explore the concept of energy conservation in electrostatics
  • Investigate the effects of gravity on charged particle motion
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the dynamics of charged particles in electric fields.

zyphriss2
Messages
18
Reaction score
0
A 13.4 cm radius thin ring carries a uniformly distributed 14.8 microC charge. A small 8.2 g sphere with a charge of 2.4 microC is placed exactly at the center of the ring and given a very small push so it moves along the ring axis (+ x axis).

How fast will the sphere be moving when it is 1.8 m from the center of the ring (ignore gravity)?





I know i can treat the ring like a point charge so e=kq/r
and (1/2)mv^2=e


I just think I am doing everything after the e=kq/r step completely wrong. My last answer was 4248m/s.
 
Physics news on Phys.org
Treat the sphere as a point charge then determine the electric field produced by the ring as a function of x.
 
the symmetry of the ring along the x-axis should greatly simplify things
 

Similar threads

Replies
11
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
6
Views
4K
Replies
4
Views
4K
Replies
11
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 5 ·
Replies
5
Views
16K