A 24.6 g pebble is stuck in the thread of a 28.7 in tire. If the tire can exert an inward radial friction force of up to 19.3 N on the pebble, how fast will the pebble be traveling with respect to the center of the wheel when it flies out tangentiall?
a = v^2 / r
The Attempt at a Solution
19.3 N = (m*v^2)/r => v^2 = (19.3 * r) / m = (19.3N * 0.36449 m) / 0.0246 kg = 16.9 m/s = final answer = INCORRECT ?
This problem is supposed to be easy, but I don't know what I'm doing wrong here. Anyone?