How High Does Water Rise in a Diving Bell?

[Fizzicist]

Homework Statement

During a test dive in 1939, prior to being accepted by the U.S. Navy, the submarine Squalus sank at a point where the depth of water was 73.0 m. The temperature at the surface was 27.0 C and at the bottom it was 7.0 C. The density of seawater is 1030 kg./m^3. A diving bell was used to rescue 33 trapped crewmen from the Squalus. The diving bell was in the form of a circular cylinder 2.30 m high, open at the bottom and closed at the top. When the diving bell was lowered to the bottom of the sea, to what height did water rise within the diving bell? (Hint: You may ignore the relatively small variation in water pressure between the bottom of the bell and the surface of the water within the bell.)

Homework Equations

p = \rhogh + pa? I really don't know...

The Attempt at a Solution

I don't even know how to approach this. I suppose I'd want to find the pressure at the bottom of the sea. This would be the pressure exerted on the gas (the air inside the bell). Then I could use the ideal gas law to solve for the change in volume, which would then give me the change in height? Am I approaching this correctly?

 

[Fizzicist]

nm...I solved it because I am a physics badass...


not really, but I solved it. :)