(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Fluid Mechanics

1. The problem statement, all variables and given/known data

You are designing a diving bell to withstand the pressure of seawater at a depth of 230.

a) What is the gauge pressure at this depth? (You can ignore changes in the density of the water with depth.)

got 2.32x10^6 Pa - masteringphysics said this is correct

b) At this depth, what is the net force due to the water outside and the air inside the bell on a circular glass window 34.0cm in diameter if the pressure inside the diving bell equals the pressure at the surface of the water? (You can ignore the small variation of pressure over the surface of the window.)

2. Relevant equations

rho = M/V

p = p0 + (rho)gh

p = F/A

F1/A1 = F2/A2

gauge pressure --> p-p0

3. The attempt at a solution

F = pA = (2.32x10^6).340m = 7.9x10^5 N - incorrect

F = pA = (2.32x10^6)(.340*230) = 1.81x10^8 N - incorrect

F = pA = (2.32x10^6)(.340^2) = 2.7x10^5 N - incorrect

I think I'm having a hard time visualizing what the question is asking, any help is greaty appreciated.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Fluid Mechanics of a diving bell

**Physics Forums | Science Articles, Homework Help, Discussion**