How High is the Watermelon When Its Kinetic Energy is 4.61J?

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SUMMARY

The discussion centers on calculating the height of a watermelon with a mass of 118 kg when its kinetic energy reaches 4.61 J after sliding down a ramp from an initial height of 5 m. The potential energy (PE) formula, PE = mgh, is essential for solving this problem. The key takeaway is that the height at which the watermelon has kinetic energy of 4.61 J can be determined by calculating the drop in height from the initial 5 m. The difference in height gives the final height above the ground.

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  • Understanding of potential energy (PE = mgh)
  • Basic knowledge of kinetic energy concepts
  • Familiarity with gravitational acceleration (g = 9.81 m/s²)
  • Ability to perform algebraic calculations
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Homework Statement



The largest watermelon ever grown had a mass of 118kg. Suppose this watermelon were exhibited on a platform 5m above the ground. After the exhibition, the watermelon is allowed to slide along to the ground along a smooth ramp. How high above the ground is the watermelon at the moment its kinetic energy is 4.61J.


Homework Equations



Can anyone give me some useful tips to solve problems like these. And how do i solve the problem =).


The Attempt at a Solution



I think i am suposed to use the PEg= mgh but other then that i don't know what i am doing haha.
 
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Welcome to PF.

Yes, potential energy is given by m*g*h.

What they are asking for is how much has it dropped to have 4.6 J imparted to its Kinetic energy.

How ever far that is, you subtract from 5 m - the original; height for your answer.
 

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