How High Must an Object Be Dropped to Achieve a Force of 203.66N?

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SUMMARY

The discussion revolves around calculating the height from which a 6.8 kg object must be dropped to achieve an impact force of 203.66 N. The key equation used is F = mg, where the gravitational acceleration is approximately 9.8 m/s². Participants clarify that maintaining the same force requires adjusting the mass of the object, as the force due to gravity remains constant. The consensus is that achieving the desired force through height alone is not feasible without altering the mass of the object.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Familiarity with basic physics concepts of force and mass
  • Ability to manipulate equations for force and velocity
NEXT STEPS
  • Research the relationship between height and impact force in free fall scenarios
  • Learn about energy conservation principles in physics
  • Explore the concept of variable mass in impact calculations
  • Study advanced kinematics to understand velocity changes during free fall
USEFUL FOR

Physics students, engineers, and anyone involved in impact testing or dynamics analysis will benefit from this discussion.

Moose720
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Homework Statement


An object with a mass of 6.8kg travels at 29.95 m/s has a force of 203.66N What height would this same object needed to be dropped from in order to achieve the same force?

Homework Equations



Not sure which formulas to use for this?

The Attempt at a Solution

 
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F = ma
 
is it "the same force or same velocity" at he end of the question
 
Same force is what I need.
 
If same force is needed then it is not possible for any height. At any height Earth's gravitation will be approx. 9.8 and F = mg and mass will remain constant.
 
it is definitely same velocity
 
I have a product that needs to pass an impact test of a 6.8kg object traveling at 29.95 m/s. What I am wanting to do it recreate this situation but in a vertical fashion. The weight of the object can vary as long as I end up with the impact force.
 
this means mass has to be variable how are you planning to vary mass
 
By adding weight to the object being dropped to achieve the desired impact force.
 
  • #10
is the velocity 29.95 at the moment of impact
 
  • #11
Yes, am I missing something?
 
  • #12
according to me the initial weight of object should be varied mathematically with a function
so that by the time it reaches ground its weight becomes 203.66 N from 68 N now we have height as a variable and some mathematical function you wish to use, final velocity of the object. try to write mass in terms of time
 
Last edited:
  • #13
thread ur question again so that more learned people can go through it and try to elucidate the situation a bit more it is getting complicated That is all i can offer
 

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