Finding Tower 2 Height to Achieve 3x Velocity

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Homework Help Overview

The discussion revolves around a physics problem involving two towers and the heights required for an object dropped from each to achieve different velocities upon reaching the ground. The original poster recalls a question from an exam regarding the height of Tower 2 needed for an object to fall at a velocity three times greater than that of an object dropped from Tower 1.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to relate the heights of the towers to the final velocities of the falling objects. There is an attempt to clarify the relationship between the velocities and the heights of the towers, particularly focusing on the condition that the object from Tower 2 must reach a velocity three times that of the object from Tower 1.

Discussion Status

The discussion is ongoing, with participants clarifying the problem statement and exploring the implications of the kinematic equations used. There is a focus on ensuring that the velocities are correctly defined in relation to the heights of the towers, but no consensus or resolution has been reached yet.

Contextual Notes

Participants note that the original problem was from an exam, which may impose constraints on the information available for discussion. The exact wording of the problem is not recalled, leading to some ambiguity in the interpretations being explored.

Frankenstein19
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Homework Statement


(I don't remember the EXACT problem because it was in an exam I took a few days ago but it was something like: If we drop the same object off of two towers, what does the height of Tower2 need to be if we want the object to fall is a velocity 3 times greater than the object falling off of tower1?

Homework Equations

The Attempt at a Solution


What I used was the vf^2 = vi^2 + 2ad and solved for d. (vf^2-vi^2)/2a = d and if vi = 0 then d=vf^2/2a

so the Height of tower 2 would have to be d=(3*vf^2)/2a, right?
 
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Close.

The question you are answering is: if the height of tower #1 is d meters, then what height does tower #2 need to be for the mass to reach triple the speed?
 
NascentOxygen said:
Close.

The question you are answering is: if the height of tower #1 is d meters, then what height does tower #2 need to be for the mass to reach triple the speed?
yes when it hits the ground
 
Frankenstein19 said:

Homework Statement


(I don't remember the EXACT problem because it was in an exam I took a few days ago but it was something like: If we drop the same object off of two towers, what does the height of Tower2 need to be if we want the object to fall is a velocity 3 times greater than the object falling off of tower1?

Homework Equations

The Attempt at a Solution


What I used was the vf^2 = vi^2 + 2ad and solved for d. (vf^2-vi^2)/2a = d and if vi = 0 then d=vf^2/2a

so the Height of tower 2 would have to be d=(3*vf^2)/2a, right?
If vf1 is the velocity of something dropped off Tower 1, then the velocity of something dropped off Tower 2, vf2 = 3 * vf1. That's how you write triple the first speed.
 
Frankenstein19 said:
yes when it hits the ground
So, what is the answer?
 

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