How High Will a Bullet Travel Fired Straight Up at 460 m/s?

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SUMMARY

A bullet fired straight up with a muzzle velocity of 460 m/s will take approximately 46.9 seconds to reach its highest point, where it will ascend to a height of about 10,670 meters. The calculations utilize the kinematic equations: vf = vi + at to determine time, where the acceleration (a) is -9.8 m/s² due to gravity. The distance traveled is then calculated using d = vt + 0.5at², confirming the effects of gravitational acceleration on the bullet's trajectory.

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A bullet is fired straight up with a muzzle velocity of 460 m/s. how long will it take it to reach its highest point and how high will that be? (The air resistance may be neglected)

i've been busting my brain over this question for almost an hour, and i just can't find a formula that will help me find this that only has one of: Distance and Time
 
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I think you should be able to find the time using the kinematic equation:

vf = vi + at

solve it for t, the problem gives you the acceleration, the final velocity and the initial velocity.

then, after you've found the time at the top of its flight, you can use

d = vt + .5at^2

to find the distance traveled.
 
what's the acceleration? it doesn't state it in the equation. or is it -9.8 m/s^2
 
right on dude
 

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