How High Will a Bullet Travel Fired Straight Up at 460 m/s?

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Homework Help Overview

The problem involves a bullet fired straight up with an initial velocity of 460 m/s, focusing on determining the time to reach its highest point and the maximum height achieved, while neglecting air resistance.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss using kinematic equations to find time and distance, with one suggesting the use of initial and final velocities along with acceleration. Questions arise regarding the value of acceleration, specifically whether it is -9.8 m/s².

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem and clarifying assumptions about acceleration. There is no explicit consensus yet, but guidance on using kinematic equations has been provided.

Contextual Notes

There is a lack of clarity regarding the acceleration value, which is critical for solving the problem. The original poster expresses difficulty in finding a suitable formula that incorporates either distance or time.

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A bullet is fired straight up with a muzzle velocity of 460 m/s. how long will it take it to reach its highest point and how high will that be? (The air resistance may be neglected)

i've been busting my brain over this question for almost an hour, and i just can't find a formula that will help me find this that only has one of: Distance and Time
 
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I think you should be able to find the time using the kinematic equation:

vf = vi + at

solve it for t, the problem gives you the acceleration, the final velocity and the initial velocity.

then, after you've found the time at the top of its flight, you can use

d = vt + .5at^2

to find the distance traveled.
 
what's the acceleration? it doesn't state it in the equation. or is it -9.8 m/s^2
 
right on dude
 

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