How Is Electric Flux Calculated Through a Cube Face with Multiple Charges?

[tag16]

Homework Statement

A particle with charge Q= 5.00 microcoulombs is located at the center of a cube of edge L= 0.100 m. In addition, six other identical charged particles -q are positioned symmetrically around Q. Determine the electric flux through one face of the cube.

Homework Equations

Flux= S E dA (the S is suppose to be an integral symbol)

The Attempt at a Solution

Flux= S E dA + S E dA

is this right so far? if so not sure what I need to do next, if not what do I need to do? thanks

 

[tiny-tim]

Hi tag16!

(have an integral: ∫ )

Flux = ∫ E dA + ∫ E dA

is this right so far? if so not sure what I need to do next, if not what do I need to do? thanks

For the charge at the centre, the flux is easy to find … just find the flux through all 6 faces, and divide by 6.

But for the other charges, yes, I think you'll have to do some integrating.