How Is Kinetic Energy Calculated from Force and Displacement?

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The discussion focuses on calculating the change in kinetic energy for a 2.0kg object subjected to a resultant force of (3i + 4j) N while moving between two points. The initial attempt incorrectly used the dot product of vectors, leading to an erroneous work calculation of 17 J instead of the correct 24 J. Clarification was provided that the dot product should yield a scalar value, emphasizing that work is a scalar quantity, not a vector. It was noted that the mass of the object is irrelevant for calculating the change in kinetic energy in this context, as work done equals the change in kinetic energy. Understanding the relationship between force, displacement, and kinetic energy is crucial for solving such problems accurately.
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Homework Statement



If the resultant force acting on a 2.0kg object is equal to (3i + 4j) N, what is the change in kinetic energy as the object moves from (7i -8j)m to (11i -5j)m


Homework Equations



w = Fd
Ek = 1/2mv2

The Attempt at a Solution



I assumed that Ek = w so I tried to solve it by getting the change in displacement and then getting the dot product using the given force (did not use the mass at all)

d= (11i -5j) - (7i -8j)
= (4i +3j)

w= (3i +4j)(4i + 3j)
= (12i + 12j)

|w| = 17 J

... this answer was totally wrong, as the answer should be 24 J.

I can't really grasp the relationship with force and kinetic energy.. would appreciate some help. thank you.
 
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Your dot product is incorrect. Remember it's also called the scalar product, because it produces a scalar, not a vector.

The dot product of two vectors, [a,b] and [c,d], is ac+bd, a simple number. In your case you have everything else correct.

Gotta kick that habit of tacking i and j back on there after evaluating the dot product!

You can also see how this is wonky because you're saying w, work, is a vector quantity, which energy is not!
 
Ohhh! thanks so much! so i really didn't need the 2.0kg?
 
No, you really don't. The force over the distance is the work done, or change in kinetic energy. If you have a very massive object, the change in kinetic energy would be the SAME, but the resulting velocity would be lower!
 
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