How Is Maximum Car Acceleration Calculated with a Friction Coefficient of 0.30?

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SUMMARY

The maximum acceleration of a car with a coefficient of static friction of 0.30 is calculated using the formula Fp = (mew)s * mg, where Fp represents the force due to friction, (mew)s is the static friction coefficient, m is the mass of the car, and g is the acceleration due to gravity (approximately 9.81 m/s²). The solution involves multiplying the static friction coefficient by the gravitational force to determine the maximum possible acceleration. This calculation does not require the mass of the car or initial velocity, simplifying the process significantly.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static friction and its coefficient
  • Basic algebra for manipulating equations
  • Familiarity with gravitational force calculations
NEXT STEPS
  • Study the relationship between friction coefficients and vehicle dynamics
  • Learn how to apply Newton's second law in various scenarios
  • Explore the effects of different surface materials on friction
  • Investigate advanced vehicle acceleration models incorporating mass and drag
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Physics students, automotive engineers, and anyone interested in vehicle dynamics and performance calculations.

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Homework Statement




What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.30?

Homework Equations


sigmaFy = Fn-mg = may = 0
sigmaFx = Fp - Ffr = max = 0
Ffr = (mew)s * Fn
Fp = Ffr = (mew)*Fn
Fp = (mew)s(mg)

mg is mass times gravity
* are multiplication
(mew)s = static friction
Fn = normal force


The Attempt at a Solution



Um...I have no clue how to solve it, any direction to point me in would be helpful. I can't see how to solve it without the mass of the car, or the initial velocity.
 
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Nevermind, it was as simple as multiplying the coefficient by gravity, sorry for the space waster.
 

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