How Is Maximum Elongation Calculated in a Spring System?

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The discussion centers on calculating the maximum elongation of a spring system involving a 2-kg block and a spring with a spring constant of 200 N/m. The initial approach suggests using the equation 1/2kx² = 1/2mv² to find maximum elongation, leading to a calculation of 0.5 m. However, participants express confusion, noting that the correct answer should be 5 m, indicating a possible typo in the problem statement. The conversation highlights the importance of verifying calculations and understanding the principles behind spring dynamics.
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A 2-kg block is attached to a horizonal ideal spring with a spring constant of 200 N/m. When the spring has its equilibrium length the block is given a speed of 5 m/s. What is the maximum elongation of the spring?

Is not the solution simply:

1/2kx2 = 1/2mv2

x = (mv2/k)0.5

x = 0.5 m?

That is incorrect, though.
 
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Looks correct to me.
 
The answer was 5m...probably a typo, just wanted to confirm.

Thanks.
 

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